Question

chemical reactions task cards created by teamwork toolbox (2017)chemical reactions13balance the chemical equation:$\text{b}_2\text{br}_6 + \text{hno}_3
ightarrow \text{b(no}_3\text{)}_3 + \text{hbr}$chemical reactions14which type of reaction?$\text{c}_6\text{h}_{12} + 9\text{o}_2
ightarrow 6\text{co}_2 + 6\text{h}_2\text{o}$synthesis decompositioncombustion single replacementdouble replacementchemical reactions15write the meaning of each symbol in this chemical equation:$\text{na(s)} + \text{h}_2\text{o(l)}
ightarrow \text{h}_2\text{(g)} + \text{naoh(aq)}$a b c dchemical reactions16how many atoms of each element?$\text{5mg}_3\text{(po}_4\text{)}_2$chemical reactions17label each type of reaction:a) $\text{a} + \text{b}
ightarrow \text{ab}$b) $\text{a} + \text{xy}
ightarrow \text{x} + \text{ay}$c) $\text{ab} + \text{xy}
ightarrow \text{xb} + \text{ay}$chemical reactions18choose the correct symbol:a) a reversible reactionb) heat being applied

Explanation:

Step1: Balance B atoms

There are 2 B on left, add coefficient 2 to $\text{B(NO}_3\text{)}_3$:
$\text{B}_2\text{Br}_6 + \text{HNO}_3
ightarrow 2\text{B(NO}_3\text{)}_3 + \text{HBr}$

Step2: Balance $\text{NO}_3^-$ groups

6 $\text{NO}_3^-$ on right, add coefficient 6 to $\text{HNO}_3$:
$\text{B}_2\text{Br}_6 + 6\text{HNO}_3
ightarrow 2\text{B(NO}_3\text{)}_3 + \text{HBr}$

Step3: Balance Br and H atoms

6 Br on left, add coefficient 6 to $\text{HBr}$ (balances H too):
$\text{B}_2\text{Br}_6 + 6\text{HNO}_3
ightarrow 2\text{B(NO}_3\text{)}_3 + 6\text{HBr}$

This reaction involves a hydrocarbon reacting with oxygen to produce carbon dioxide and water, which fits the definition of a combustion reaction.

Each symbol indicates the physical state of the substance: (s) = solid, (l) = liquid, (g) = gas, (aq) = aqueous (dissolved in water).

Step1: Calculate Mg atoms

Multiply coefficient, subscript: $5 \times 3 = 15$

Step2: Calculate P atoms

Multiply coefficient, subscript: $5 \times 2 = 10$

Step3: Calculate O atoms

Multiply coefficient, subscripts: $5 \times 4 \times 2 = 40$

Answer:

$\text{B}_2\text{Br}_6 + 6\text{HNO}_3
ightarrow 2\text{B(NO}_3\text{)}_3 + 6\text{HBr}$

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