Question

a chemist mixes 200 milliliters of a solution that is 55% acid with 425 milliliters of pure acid. answer the questions below. do not do any rounding. (a) how many milliliters of acid are in the resulting mixture? milliliters (b) what percentage of the resulting mixture is acid? %

Explanation:

Step1: Calculate acid in 55% solution

$200\times0.55 = 110$ (milliliters)

Step2: Calculate total acid in mixture

The pure - acid is 425 milliliters. Total acid = acid in 55% solution+pure acid, so $110 + 425=535$ (milliliters)

Step3: Calculate total volume of mixture

Total volume = volume of 55% solution+volume of pure acid, $200 + 425 = 625$ (milliliters)

Step4: Calculate percentage of acid in mixture

Percentage of acid=$\frac{535}{625}\times100\%=85.6\%$

Answer:

(a) 535 milliliters
(b) 85.6%