Question

a chemist working as a safety inspector finds an unmarked bottle in a lab cabinet. a note on the door of the cabinet says the cabinet is used bottles of tetrahydrofuran, glycerol, pentane, carbon tetrachloride, and chloroform. the chemist plans to try to identify the unknown liquid by measuring the density and comparing to known densities. first, from her collection safety data sheets (msds), the chemist finds the following information: liquid density tetrahydrofuran 0.89 g·cm^(-3) glycerol 1.3 g·cm^(-3) pentane 0.63 g·cm^(-3) carbon tetrachloride 1.6 g·cm^(-3) chloroform 1.5 g·cm^(-3) next, the chemist measures the volume of the unknown liquid as 1.118 l and the mass of the unknown liquid as 700. g. your answer calculate the density of the liquid. round your answer to 3 significant digits. g·cm^(-3) given the data above, is it possible to identify the liquid? yes no if it is possible to identify the liquid, do so. tetrahydrofuran glycerol pentane carbon tetrachloride chloroform

Explanation:

Step1: Convert volume to $cm^3$

Since $1\ L = 1000\ cm^3$, then $V = 1.118\ L=1.118\times1000 = 1118\ cm^3$.

Step2: Calculate density

The formula for density is $
ho=\frac{m}{V}$. Given $m = 700\ g$ and $V = 1118\ cm^3$, so $
ho=\frac{700\ g}{1118\ cm^3}\approx0.626\ g\cdot cm^{-3}$.

Answer:

Calculate the density of the liquid: $0.626\ g\cdot cm^{-3}$
Given the data above, is it possible to identify the liquid?: yes
If it is possible to identify the liquid, do so.: pentane