Question

in circle t with $m\angle svu = 41^\circ$, find the measure of minor arc $\widehat{su}$.

Explanation:

Step1: Recall inscribed angle theorem

The measure of an inscribed angle is half the measure of its intercepted arc. So, $m\angle SVU = \frac{1}{2}m\overset{\frown}{SU}$.

Step2: Solve for arc measure

Rearrange the formula to isolate $m\overset{\frown}{SU}$: $m\overset{\frown}{SU} = 2 \times m\angle SVU$.
Substitute $m\angle SVU = 41^\circ$:
$m\overset{\frown}{SU} = 2 \times 41^\circ$

Answer:

$82^\circ$