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a class has 56 students (bottles of) the carrot mustard. the graph show…

Question

a class has 56 students (bottles of) the carrot mustard. the graph shows how many students (bottles) each... (graph: amount of mustard, number line with xs) if you distribute 56 of these mustards equally among 12 bottles, how much will each bottle contain? options: 5/12 cup, 12/56 cup, 4/12 cup, 12/5 cup?

Explanation:

Step1: Determine total mustard

First, find total mustard from the jars. Let's assume each jar's quantity: Jar 1: \( \frac{9}{10} \) cups, Jar 2: \( 1\frac{7}{10} \) cups, Jar 3: \( \frac{4}{10} \) cups. Convert mixed number: \( 1\frac{7}{10}=\frac{17}{10} \). Total: \( \frac{9}{10}+\frac{17}{10}+\frac{4}{10}=\frac{9 + 17+4}{10}=\frac{30}{10}=3 \) cups.

Step2: Distribute to 10 students

Divide total mustard (3 cups) by 10 students: \( 3\div10=\frac{3}{10} \) cups per student? Wait, no—wait, the jars: Wait, maybe the jars are \( \frac{9}{10} \), \( 1\frac{7}{10} \), \( \frac{4}{10} \). Wait, total is \( \frac{9 + 17 + 4}{10}=\frac{30}{10}=3 \) cups. Then distribute 3 cups to 10 students: \( \frac{3}{10} \) cups? But wait, the options: Wait, maybe I misread. Wait, the problem says "distribute the mustard equally among 10 students". Wait, total mustard: let's recheck. Jar 1: 2 units? Wait, the diagram: maybe each "X" is a unit? Wait, maybe the first jar has \( \frac{9}{10} \)? No, maybe the jars are \( \frac{9}{10} \), \( 1\frac{7}{10} \), \( \frac{4}{10} \). Wait, \( 1\frac{7}{10} = \frac{17}{10} \), so total is \( \frac{9}{10} + \frac{17}{10} + \frac{4}{10} = \frac{30}{10} = 3 \) cups. Then 3 cups divided by 10 students: \( \frac{3}{10} \) cups? But the options include \( \frac{3}{10} \) cup? Wait, the options are \( \frac{9}{10} \) cup, \( 1\frac{7}{10} \) cup, \( \frac{4}{10} \) cup, \( \frac{3}{10} \) cup? Wait, maybe I miscalculated. Wait, total mustard: let's count the jars. First jar: 9/10? Second: 17/10 (1 and 7/10), third: 4/10. Sum: 9 + 17 + 4 = 30, so 30/10 = 3. Then 3 divided by 10 is 3/10. So each student gets \( \frac{3}{10} \) cup? Wait, but maybe the jars are different. Wait, maybe the first jar is \( \frac{9}{10} \), second \( 1\frac{7}{10} \), third \( \frac{4}{10} \). Total is 3 cups. Then 3 cups / 10 students = \( \frac{3}{10} \) cup per student.

Answer:

\( \frac{3}{10} \) cup (assuming the options include this; if the options are as listed, and the calculation leads to \( \frac{3}{10} \), then that's the answer. Wait, maybe I misread the jars. Alternatively, maybe the total is \( \frac{9}{10} + 1\frac{7}{10} + \frac{4}{10} = \frac{9 + 17 + 4}{10} = \frac{30}{10} = 3 \), then 3/10 per student. So the answer is \( \frac{3}{10} \) cup.