Question

clean water from a public drinking fountain
the chemical equation for this
reaction is shown below.
\\(4\\,\mathrm{hcl}(aq) + \mathrm{o}_2(g) \
ightarrow 2\\,\mathrm{h}_2\mathrm{o}(l) +
\\)complete the table to show the state
of matter for each substance in the
equation.

substance	state of matter
oxygen (\\(\mathrm{o}_2\\))	\\(\boldsymbol{\downarrow}\\)
water (\\(\mathrm{h}_2\mathrm{o}\\))	\\(\boldsymbol{\downarrow}\\)
chlorine (\\(\mathrm{cl}_2\\))	\\(\boldsymbol{\downarrow}\\)

Explanation:

Step1: Analyze HCl state

Hydrochloric acid (HCl) in the equation is labeled (aq), which stands for aqueous (dissolved in water). So HCl is aqueous.

Step2: Analyze O₂ state

Oxygen (O₂) is labeled (g), meaning gas. So O₂ is gas.

Step3: Analyze H₂O state

Water (H₂O) is labeled (l), meaning liquid. So H₂O is liquid.

Step4: Analyze Cl₂ state (assuming the reaction produces Cl₂, and from typical reactions, Cl₂ is a gas at room temp)

Chlorine (Cl₂) is a gas under standard conditions, so its state is gas.

Answer:

Substance	State of matter
oxygen (O₂)	gas (g)
water (H₂O)	liquid (l)
chlorine (Cl₂)	gas (g)

(Note: The chemical equation in the problem seems to be incomplete, but assuming the full reaction is \( 4\text{HCl}(aq) + \text{O}_2(g)
ightarrow 2\text{H}_2\text{O}(l) + 2\text{Cl}_2(g) \) based on common redox reactions, we determine the states as above.)