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does the colorado avalanche nhl hockey team perform differently in game…

Question

does the colorado avalanche nhl hockey team perform differently in games that go into overtime (or shootout) compared to games that dont? the table shows data for the colorado avalanche over six seasons.

seasongames playedtotal winsovertime or shootout games playedwins in overtime or shootout games
2021-2282561412
2020-215639169
2019-207042179
2018-198238162
2017-188243189
total4542699546

let a represent the event \the avalanche wins a game\ and b represent \the game goes to overtime or shootout\.

  1. use the data to estimate the probabilities. explain or show your reasoning.

a. ( p(a) )

b. ( p(b) )

c. ( p(a \text{ and } b) )

d. ( p(a|b) )

Explanation:

Response
1a. \( P(A) \)

Step1: Recall probability formula

Probability of an event \( A \) is \( P(A)=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \). For \( P(A) \), favorable outcomes are total wins, total outcomes are total games played.

Step2: Identify values

Total wins (favorable for \( A \)) = 269, Total games played = 454.

Step3: Calculate \( P(A) \)

\( P(A)=\frac{269}{454}\approx0.5925 \)

1b. \( P(B) \)

Step1: Recall probability formula

\( P(B)=\frac{\text{Number of games in overtime/shootout}}{\text{Total games played}} \).

Step2: Identify values

Games in overtime/shootout = 95, Total games played = 454.

Step3: Calculate \( P(B) \)

\( P(B)=\frac{95}{454}\approx0.2092 \)

1c. \( P(A \text{ and } B) \)

Step1: Recall probability formula

\( P(A \text{ and } B)=\frac{\text{Wins in overtime/shootout}}{\text{Total games played}} \).

Step2: Identify values

Wins in overtime/shootout = 46, Total games played = 454.

Step3: Calculate \( P(A \text{ and } B) \)

\( P(A \text{ and } B)=\frac{46}{454}\approx0.1013 \)

1d. \( P(A|B) \)

Answer:

s:
a. \( \boldsymbol{\frac{269}{454}\approx0.593} \) (or exact fraction \( \frac{269}{454} \))
b. \( \boldsymbol{\frac{95}{454}\approx0.209} \) (or exact fraction \( \frac{95}{454} \))
c. \( \boldsymbol{\frac{46}{454}\approx0.101} \) (or exact fraction \( \frac{23}{227} \))
d. \( \boldsymbol{\frac{46}{95}\approx0.484} \) (or exact fraction \( \frac{46}{95} \))