Question

the combustion of propane (\\(\ce{c_{3}h_{8}}\\)) with oxygen forms \\(\ce{co_{2}}\\) and \\(\ce{h_{2}o}\\) according to the given equation. select the single best answer for each part.\\(\ce{c_{3}h_{8}(g) + 5o_{2}(g) \
ightarrow 3co_{2}(g) + 4h_{2}o(l)}\\) \\(\delta h = -531 \frac{\text{kcal}}{\text{mol}}\\)\
part 1 of 3\
is heat absorbed or released?

Explanation:

The enthalpy change ($\Delta H$) for the reaction is given as $-531\ \frac{\text{kcal}}{\text{mol}}$. A negative $\Delta H$ indicates that the reaction is exothermic, meaning heat is released during the combustion of propane.

Answer:

released