Question

compare the total mass of the reactants to the total mass of the products.
what choice demonstrates the law of conservation of mass?
22 g c + 42 g o₂ → 44 g co₂
170 g fe₂o₃ + 12 g c → 112 g fe + 44 g co₂
12 g mg + 72 g hcl → 95 g mgcl₂ + 1 g h₂
60 g c₆h₁₂ + 224 g o₂ → 176 g co₂ + 108 g h₂o

Explanation:

Step1: Calculate reactant mass (Option1)

$22\ \text{g} + 42\ \text{g} = 64\ \text{g}$

Step2: Compare to product mass (Option1)

Product mass = $44\ \text{g}$, $64\ \text{g}
eq 44\ \text{g}$

Step3: Calculate reactant mass (Option2)

$170\ \text{g} + 12\ \text{g} = 182\ \text{g}$

Step4: Compare to product mass (Option2)

$112\ \text{g} + 44\ \text{g} = 156\ \text{g}$, $182\ \text{g}
eq 156\ \text{g}$

Step5: Calculate reactant mass (Option3)

$12\ \text{g} + 72\ \text{g} = 84\ \text{g}$

Step6: Compare to product mass (Option3)

$95\ \text{g} + 1\ \text{g} = 96\ \text{g}$, $84\ \text{g}
eq 96\ \text{g}$

Step7: Calculate reactant mass (Option4)

$60\ \text{g} + 224\ \text{g} = 284\ \text{g}$

Step8: Compare to product mass (Option4)

$176\ \text{g} + 108\ \text{g} = 284\ \text{g}$, $284\ \text{g} = 284\ \text{g}$

Answer:

D. $60\ \text{g}\ \text{C}_5\text{H}_{12} + 224\ \text{g}\ \text{O}_2
ightarrow 176\ \text{g}\ \text{CO}_2 + 108\ \text{g}\ \text{H}_2\text{O}$