Question

complete the equations.
489 = 4 hundreds + 8 tens + 9 ones
489 = 0 hundreds + \square tens + 9 ones
489 = 0 hundreds + 0 tens + \square ones

Explanation:

Step1: Recall place value

We know that 1 hundred = 100, 1 ten = 10, and 1 one = 1. For the second equation, we have \(489 = 0\times100 + \square\times10 + 9\times1\). So, \(0 + 10\square+ 9 = 489\). Subtract 9 from both sides: \(10\square= 489 - 9 = 480\). Then, \(\square=\frac{480}{10}=48\).

Step2: Solve for the third equation

For the third equation, \(489 = 0\times100 + 0\times10 + \square\times1\). So, \(0 + 0+\square= 489\), which means \(\square = 489\).

Answer:

For the second equation, the number of tens is \(\boldsymbol{48}\). For the third equation, the number of ones is \(\boldsymbol{489}\).