Question

complete the following statement. use the integers that are closest to the number in the middle.
\square < -\sqrt{95} < \square

Explanation:

Step1: Find perfect squares near 95

We know that \(9^2 = 81\) and \(10^2 = 100\). So, \(81<95<100\).

Step2: Take square roots

Taking square roots of each part, we get \(\sqrt{81}<\sqrt{95}<\sqrt{100}\), which simplifies to \(9 < \sqrt{95}<10\).

Step3: Apply negative sign

Multiplying each part by -1 (and reversing the inequality signs), we get \(- 10<-\sqrt{95}<-9\).

Answer:

\(-10 < -\sqrt{95} < -9\)