QUESTION IMAGE
Question
complete the proof that $overline{hi} parallel overline{fg}$.
| statement | reason | |
|---|---|---|
| 2 | $overline{hi} \cong \overline{fg}$ | given |
| 3 | $overline{fh} \cong \overline{fh}$ | reflexive property of congruence |
| 4 | $\triangle fhi \cong \triangle hfg$ | sss |
| 5 | $\angle fhi \cong \angle gfh$ | cpctc |
| 6 | $overline{hi} \parallel \overline{fg}$ |
Step1: Identify the angles
We have $\angle FHI \cong \angle GFH$ from step 5 (CPCTC). These are alternate interior angles formed by the transversal $\overline{FH}$ intersecting $\overline{HI}$ and $\overline{FG}$.
Step2: Apply the Alternate Interior Angles Theorem
The Alternate Interior Angles Theorem states that if alternate interior angles are congruent, then the two lines cut by the transversal are parallel. Since $\angle FHI \cong \angle GFH$, by the Alternate Interior Angles Theorem, $\overline{HI} \parallel \overline{FG}$.
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Alternate Interior Angles Theorem