Question

complete the tasks to subtract the polynomials vertically. (1.3t³ + 0.4t² - 24t)-(0.6t² + 8 - 18t) what is the additive inverse of the polynomial being subtracted? -0.6t²+(-8)+(-18t) -0.6t²+(-8)+18t -0.6t² + 8 - 18t 0.6t²+(-8)+18t complete choose the correct values for a, b, c, and d that align like - terms to find the sum vertically. 1.3t³ + 0.4t²+(-24t) + a + b + c + d a=(-0.6t²) b = (-8) c = 18t d = 0t³ a = 0t³ b=(-0.6t²) c = 18t d = (-8) a = 0t³ b=(-0.6t²) c = (-8) d = 18t done

Explanation:

Step1: Recall additive inverse concept

The additive inverse of a polynomial \(a + b + c\) is \(-a - b - c\). The polynomial being subtracted is \(0.6t^{2}+8 - 18t\).

Step2: Find the additive - inverse

Change the sign of each term. The additive inverse is \(-0.6t^{2}+(- 8)+18t\).
For finding \(A\), \(B\), \(C\), and \(D\) to align like - terms:
The first polynomial is \(1.3t^{3}+0.4t^{2}-24t\). The additive inverse of the second polynomial is \(-0.6t^{2}-8 + 18t\).
To align like - terms, we have \(A = 0t^{3}\), \(B=-0.6t^{2}\), \(C = (-8)\), \(D = 18t\).

Answer:

A = \(0t^{3}\), B = \((-0.6t^{2})\), C = \((-8)\), D = \(18t\)