Question

complete the tasks to subtract the polynomials vertically.
(1.3t³ + 0.4t² − 24t) − (0.6t² + 8 − 18t)
what is the additive inverse of the polynomial being subtracted?
○ −0.6t² + (−8) + (−18t)
○ −0.6t² + (−8) + 18t
○ −0.6t² + 8 − 18t
○ 0.6t² + (−8) + 18t
done

Explanation:

The polynomial being subtracted is \(0.6t^{2}+8 - 18t\). The additive inverse of a polynomial \(P(t)\) is \(-P(t)\), which means we change the sign of each term. So, the additive inverse of \(0.6t^{2}+8 - 18t\) is \(-0.6t^{2}-8 + 18t\), which can be written as \(-0.6t^{2}+(-8)+18t\).

Answer:

B. \(-0.6t^{2}+(-8)+18t\)