Question

congruent triangles (topic 5)
to show that △rqp≅△psr by sss, what must be the value of x?

Explanation:

Step1: Set equal corresponding sides

Since $\triangle RQP\cong\triangle PSR$ by SSS, we set $2x + 3=4x - 7$.

Step2: Solve the equation for $x$

First, move the $x$ - terms to one side: $4x-2x=3 + 7$.
Then simplify: $2x=10$.
Divide both sides by 2: $x = 5$.

Answer:

$5$