Question

consider the atoms that are bonded to two or more other atoms. highlight the non - hydrogen atoms with an sp hybridization in red, an sp² hybridization in green, and an sp³ hybridization in blue.

Explanation:

Step1: Recall hybridization rules

• $sp$ hybridization: 2 electron - groups around the atom.
• $sp^{2}$ hybridization: 3 electron - groups around the atom.
• $sp^{3}$ hybridization: 4 electron - groups around the atom.

Step2: Analyze carbon atoms in the given molecule

• $sp$ hybridization: There are no non - hydrogen atoms with $sp$ hybridization in this molecule.
• $sp^{2}$ hybridization: Carbon atoms in the aromatic rings (benzene - like rings) and the carbonyl carbon ($C = O$) have 3 electron - groups around them. So, carbon atoms in the aromatic rings and the carbonyl carbon should be highlighted in green.
• $sp^{3}$ hybridization: The carbon atom in the methyl group attached to the aromatic ring and the carbon atom between the aromatic ring and the carbonyl group have 4 electron - groups around them. So, these carbon atoms should be highlighted in blue.

Answer:

Highlight carbon atoms in aromatic rings and carbonyl carbon in green. Highlight methyl - attached carbon and the carbon between aromatic ring and carbonyl in blue. No non - hydrogen atoms to be highlighted in red.