Question

consider $y = -3x + 1$.

a. complete the table for the equation.

$x$	$y$
1	\boxed{}
2	\boxed{}

Explanation:

Step1: Substitute x = 0 into the equation

We have the equation \( y = -3x + 1 \). When \( x = 0 \), we substitute \( x \) with 0 in the equation:
\( y = -3(0) + 1 \)
\( y = 0 + 1 = 1 \)

Step2: Substitute x = 1 into the equation

When \( x = 1 \), substitute \( x \) with 1:
\( y = -3(1) + 1 \)
\( y = -3 + 1 = -2 \)

Step3: Substitute x = 2 into the equation

When \( x = 2 \), substitute \( x \) with 2:
\( y = -3(2) + 1 \)
\( y = -6 + 1 = -5 \)

Answer:

For \( x = 0 \), \( y = 1 \); for \( x = 1 \), \( y = -2 \); for \( x = 2 \), \( y = -5 \)

So the completed table is:

\( x \)	\( y \)
1	-2
2	-5