Question

consider the ions fe²⁺ and o²⁻. how many protons and electrons does each of these ions possess? protons in fe²⁺ electrons in fe²⁺ protons in o²⁻ electrons in o²⁻

Explanation:

Step1: Recall atomic number of elements

The atomic number of Fe (iron) is 26 and of O (oxygen) is 8. The number of protons is equal to the atomic number.

Step2: Calculate electrons in Fe²⁺

Fe has 26 electrons in its neutral state. Fe²⁺ has lost 2 electrons. So, number of electrons = 26 - 2 = 24.

Step3: Calculate electrons in O²⁻

O has 8 electrons in its neutral state. O²⁻ has gained 2 electrons. So, number of electrons = 8+ 2 = 10.

Answer:

protons in Fe²⁺: 26
electrons in Fe²⁺: 24
protons in O²⁻: 8
electrons in O²⁻: 10