Question

consider the molecule below. determine the molecular geometry at each of the 2 labeled carbons.

Explanation:

Step1: Analyze C1 (the positively charged carbon)

The positively charged carbon (C1) is bonded to three atoms (or groups) and has no lone pairs. Using VSEPR theory, the electron - domain geometry and molecular geometry for a central atom with 3 bonding domains and 0 lone pairs is trigonal planar.

Step2: Analyze C2 (the negatively charged carbon)

The negatively charged carbon (C2) is bonded to four atoms (or groups) and has no lone pairs. Using VSEPR theory, the electron - domain geometry and molecular geometry for a central atom with 4 bonding domains and 0 lone pairs is tetrahedral.

Looking at the options, the option with C1 = trigonal planar and C2 = tetrahedral is the correct one (the teal - colored option in the image).

Answer:

The correct option is the one with "C1 = trigonal planar, C2 = tetrahedral" (the teal - colored option among the given choices).