Question

consider triangle abc. the legs have a length of 5 units each.
what is the length of the hypotenuse of the triangle?
○ 5 units
○ $5\sqrt{2}$ units
○ 10 units
○ $10\sqrt{2}$ units

Explanation:

Step1: Apply Pythagorean theorem

For right triangle $ABC$, $c^2 = a^2 + b^2$, where $a=5$, $b=5$, $c$ is hypotenuse.
$$c^2 = 5^2 + 5^2$$

Step2: Calculate sum of squares

$$c^2 = 25 + 25 = 50$$

Step3: Solve for hypotenuse $c$

$$c = \sqrt{50} = 5\sqrt{2}$$

Answer:

B. $5\sqrt{2}$ units