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Question
- a container holds three gases: oxygen, carbon dioxide, and helium. the partial pressures of the three gases are 2.00 atm, 3.00 atm, and 4.00 atm, respectively. what is the total pressure inside the container?
- 80.0 liters of oxygen is collected over water at 50 °c. ($p_{h2o}$ @ 50 c = 12.334 kpa). the atmospheric pressure in the room is 96.00 kpa. what is the partial pressure of the oxygen?
- if 60.0 l of nitrogen is collected over water at 40.0 °c when the atmospheric pressure is 760.0 mm hg, what is the partial pressure of the nitrogen? ($p_{h2o}$ @ 40 c = 7.38 kpa)
- a mixture of 40.0 g of oxygen and 40.0 g of helium has a total pressure of 0.900 atm. what is the partial pressure of each gas?
- a mixture of 66% nitrogen and 33% neon gases has a total mass of 15.0 g. what is the density of this gas mixture at 350 k and 7.0 atm? assume ideal gas behavior.
- a mixture of gases contains 2.14 g of $n_2$, 5.85 g of $h_2$, and 4.18 g of $nh_3$. if the total pressure of the mixture is 4.58 atm, what is the partial pressure of each component?
- three gases (8.00 g of methane, $ch_4$, 18.0 g of ethane, $c_2h_6$, and an unknown amount of propane, $c_3h_8$) were added to the same 10.0 l container. at 23.0 °c, the total pressure in the container was measured to be 4.43 atm. calculate the partial pressure of each gas in the container.
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Problem 9
Step1: Sum partial pressures
$P_{total} = P_{O_2} + P_{CO_2} + P_{He}$
Step2: Substitute given values
$P_{total} = 2.00\ \text{atm} + 3.00\ \text{atm} + 4.00\ \text{atm}$
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Problem 10
Step1: Subtract water vapor pressure
$P_{O_2} = P_{atm} - P_{H_2O}$
Step2: Substitute given values
$P_{O_2} = 96.00\ \text{kPa} - 12.334\ \text{kPa}$
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Problem 11
Step1: Convert atm to kPa
$760.0\ \text{mm Hg} = 101.325\ \text{kPa}$
Step2: Subtract water vapor pressure
$P_{N_2} = 101.325\ \text{kPa} - 7.38\ \text{kPa}$
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Problem 12
Step1: Calculate moles of each gas
$n_{O_2} = \frac{40.0\ \text{g}}{32.00\ \text{g/mol}} = 1.25\ \text{mol}$, $n_{He} = \frac{40.0\ \text{g}}{4.003\ \text{g/mol}} \approx 9.99\ \text{mol}$
Step2: Find mole fractions
$\chi_{O_2} = \frac{1.25}{1.25+9.99} \approx 0.111$, $\chi_{He} = 1 - 0.111 = 0.889$
Step3: Calculate partial pressures
$P_{O_2} = \chi_{O_2}P_{total}$, $P_{He} = \chi_{He}P_{total}$
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Problem 13
Step1: Find masses of each gas
$m_{N_2} = 0.66 \times 15.0\ \text{g} = 9.9\ \text{g}$, $m_{Ne} = 0.33 \times 15.0\ \text{g} = 4.95\ \text{g}$
Step2: Calculate total moles
$n_{N_2} = \frac{9.9\ \text{g}}{28.02\ \text{g/mol}} \approx 0.353\ \text{mol}$, $n_{Ne} = \frac{4.95\ \text{g}}{20.18\ \text{g/mol}} \approx 0.245\ \text{mol}$
$n_{total} = 0.353 + 0.245 = 0.598\ \text{mol}$
Step3: Use ideal gas law for volume
$V = \frac{n_{total}RT}{P} = \frac{0.598\ \text{mol} \times 0.0821\ \text{L·atm/(mol·K)} \times 350\ \text{K}}{7.0\ \text{atm}} \approx 2.47\ \text{L}$
Step4: Calculate density
$
ho = \frac{m_{total}}{V}$
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Problem 14
Step1: Calculate moles of each gas
$n_{N_2} = \frac{2.14\ \text{g}}{28.02\ \text{g/mol}} \approx 0.0764\ \text{mol}$, $n_{H_2} = \frac{5.85\ \text{g}}{2.016\ \text{g/mol}} \approx 2.90\ \text{mol}$, $n_{NH_3} = \frac{4.18\ \text{g}}{17.03\ \text{g/mol}} \approx 0.245\ \text{mol}$
Step2: Find total moles
$n_{total} = 0.0764 + 2.90 + 0.245 \approx 3.221\ \text{mol}$
Step3: Calculate mole fractions and partial pressures
$\chi_i = \frac{n_i}{n_{total}}$, $P_i = \chi_i P_{total}$
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Problem 15
Step1: Calculate moles of known gases
$n_{CH_4} = \frac{8.00\ \text{g}}{16.04\ \text{g/mol}} = 0.499\ \text{mol}$, $n_{C_2H_6} = \frac{18.0\ \text{g}}{30.07\ \text{g/mol}} \approx 0.599\ \text{mol}$
Step2: Find total moles via ideal gas law
$n_{total} = \frac{P_{total}V}{RT} = \frac{4.43\ \text{atm} \times 10.0\ \text{L}}{0.0821\ \text{L·atm/(mol·K)} \times 296.15\ \text{K}} \approx 1.82\ \text{mol}$
Step3: Find moles of propane
$n_{C_3H_8} = 1.82 - 0.499 - 0.599 = 0.722\ \text{mol}$
Step4: Calculate partial pressures
$P_i = \frac{n_i}{n_{total}}P_{total}$
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- $9.00\ \text{atm}$
- $83.67\ \text{kPa}$
- $93.95\ \text{kPa}$
- $P_{O_2} = 0.0999\ \text{atm}$, $P_{He} = 0.800\ \text{atm}$
- $\approx 6.07\ \text{g/L}$
- $P_{N_2} = 0.111\ \text{atm}$, $P_{H_2} = 4.17\ \text{atm}$, $P_{NH_3} = 0.298\ \text{atm}$
- $P_{CH_4} = 1.21\ \text{atm}$, $P_{C_2H_6} = 1.45\ \text{atm}$, $P_{C_3H_8} = 1.77\ \text{atm}$