Question

a copper rod that has a mass of 200.0 g has an initial temperature of 20.0 °c and is heated to 40.0 °c. if 1,540 j of heat are needed to heat the rod, what is the specific heat of copper? use $q = mc_pdelta t$. 0.385 j/(g·°c) 0.0649 j/(g·°c) 0.0130 j/(g·°c) 0.193 j/(g·°c)

Explanation:

Step1: Rearrange formula for $C_p$

$C_p = \frac{q}{m\Delta T}$

Step2: Calculate temperature change

$\Delta T = 40.0^\circ\text{C} - 20.0^\circ\text{C} = 20.0^\circ\text{C}$

Step3: Substitute values into formula

$C_p = \frac{1540\ \text{J}}{200.0\ \text{g} \times 20.0^\circ\text{C}}$

Step4: Compute the result

$C_p = \frac{1540}{4000} = 0.385\ \text{J}/(\text{g·}^\circ\text{C})$

Answer:

0.385 J/(g·°C)