Question

current attempt in progress
how many joules of energy are required to raise the temperature of 50.0 g of water from 25°c to 100.°c?
1.6 x 10⁴ j
5.0 x 10¹ j
9.0 x 10² j
2.1 x 10⁴ j

Explanation:

Step1: Identify the formula

The formula for heat energy is $Q = mc\Delta T$, where $Q$ is the heat energy, $m$ is the mass, $c$ is the specific - heat capacity, and $\Delta T$ is the change in temperature. The specific - heat capacity of water $c = 4.18\ J/(g\cdot^{\circ}C)$.

Step2: Calculate the change in temperature

$\Delta T=T_{2}-T_{1}=100^{\circ}C - 25^{\circ}C=75^{\circ}C$.

Step3: Substitute values into the formula

$m = 50.0\ g$, $c = 4.18\ J/(g\cdot^{\circ}C)$, and $\Delta T = 75^{\circ}C$. Then $Q=50.0\ g\times4.18\ J/(g\cdot^{\circ}C)\times75^{\circ}C$.
$Q = 50\times4.18\times75\ J=15675\ J\approx1.6\times 10^{4}\ J$.

Answer:

$1.6\times 10^{4}\ J$