QUESTION IMAGE
Question
current objective use systems of equations to investigate profits switch question if cost is represented by $c(x)=1.8x + 10000$ and revenues are represented by $r(x)=8.5x$, which equation could be used to find the break - even point? select the correct answer below: $6.7x = 1.8x+10000$ $6.7x=-10000$ $8.5x = 1.8x - 10000$ $10.3x = 10000$ $8.5x = 1.8x + 10000$
Step1: Recall break - even point concept
At break - even point, cost equals revenue.
Step2: Set up the equation
Since $C(x)=1.8x + 10000$ and $R(x)=8.5x$, we set $R(x)=C(x)$. So, $8.5x=1.8x + 10000$.
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E. $8.5x = 1.8x + 10,000$