Question

cuso₄·2h₂o
spell out the full name of the compound.
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part d
aluminum nitrate dihydrate
express your answer as a chemical formula.
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Explanation:

First Question (Naming $\boldsymbol{\ce{CuSO4\cdot 2H2O}}$)

Step1: Identify the ionic compound and water of crystallization

$\ce{CuSO4}$ is copper(II) sulfate (since $\ce{Cu^{2+}}$ and $\ce{SO4^{2-}}$). The $\ce{\cdot 2H2O}$ means 2 water molecules (dihydrate).

Step2: Combine the names

The full name is copper(II) sulfate dihydrate.

Step1: Determine ions and their charges

Aluminum ion: $\ce{Al^{3+}}$, nitrate ion: $\ce{NO3^-}$, water: $\ce{H2O}$. Dihydrate means 2 $\ce{H2O}$.

Step2: Balance charges for aluminum nitrate

To balance $\ce{Al^{3+}}$ and $\ce{NO3^-}$, formula is $\ce{Al(NO3)3}$.

Step3: Add water of crystallization

Add $\ce{\cdot 2H2O}$ for dihydrate. So formula is $\ce{Al(NO3)3\cdot 2H2O}$.

Answer:

copper(II) sulfate dihydrate

Part D (Formula for aluminum nitrate dihydrate)