Question

b) a dancer with a mass of 80kg is standing with one foot. the dancer exerts pressure of 20,000 pa on the floor. what is the surface area of the foot of the dancer?

Explanation:

Step1: Calculate the force exerted by the dancer

The force \(F\) exerted by the dancer is equal to the weight \(W\). Using the formula \(W = mg\), where \(m = 80kg\) and \(g= 9.8m/s^{2}\). So \(F=W=mg = 80\times9.8N=784N\).

Step2: Use the pressure - area formula

The pressure formula is \(P=\frac{F}{A}\), where \(P = 20000Pa\) and \(F = 784N\). Rearranging for area \(A\), we get \(A=\frac{F}{P}\).
Substitute \(F = 784N\) and \(P = 20000Pa\) into the formula: \(A=\frac{784}{20000}m^{2}=0.0392m^{2}\).

Answer:

\(0.0392m^{2}\)