Question

1 dariush ate \\(\frac{3}{8}\\) of the coffee cake while eton ate \\(\frac{4}{8}\\). how much of the coffee cake did the boys eat? \\(\frac{7}{8}\\) of the coffee cake \\(\frac{3}{8}+\frac{4}{8}=\frac{7}{8}\\) 2 the maximum weight allowed at one time on a walking bridge is 400,000 grams. can these people safely stand on the bridge together? yes kyle 71 kg cara 59 kg betty 66 kg roge 79 kg devin 86 kg how many grams do they weigh all together? 361000 grams 3 multiply. show your work. \\(\

$$\begin{array}{r}483\\\\*\\ \\ \\ \\ 9\\\\\\hline4347\\end{array}$$

\\) estimate: answer: 4 use your fraction circle pieces to solve this problem. if \\(\triangle\\) is \\(\frac{1}{4}\\), then what is the whole? 5 writing/reasoning solve problem 3 using a different strategy. show your work.

Explanation:

Problem 1

Step1: Identify the fractions to add

Dariush ate $\frac{3}{8}$ and Eton ate $\frac{4}{8}$. We need to add these two fractions.

Step2: Add the numerators (same denominator)

For fractions with the same denominator, we add the numerators and keep the denominator. So $\frac{3}{8}+\frac{4}{8}=\frac{3 + 4}{8}=\frac{7}{8}$.

Step1: Convert all weights to grams

1 kg = 1000 grams. So Kyle: $71\times1000 = 71000$ g, Cara: $59\times1000 = 59000$ g, Betty: $66\times1000 = 66000$ g, Roge: $79\times1000 = 79000$ g, Devin: $86\times1000 = 86000$ g.

Step2: Sum all weights in grams

Total weight = $71000+59000 + 66000+79000+86000$. Let's calculate step by step: $71000+59000=130000$; $130000+66000 = 196000$; $196000+79000 = 275000$; $275000+86000 = 361000$ g.

Step3: Compare with maximum weight

Maximum weight is 400,000 grams. Since $361000<400000$, they can stand together.

(Second part: Total weight in grams):
As calculated above, the total weight is 361000 grams.

Answer:

$\frac{7}{8}$

Problem 2 (First part: Can they stand together?)