Question

day 5 calculate the net force and write the direction of movement for questions 1 - 4. 1. net force: direction: 2. net force: direction: 3. net force: direction: 4. net force: direction:

Explanation:

Step1: Define right - direction as positive

Let forces acting to the right be positive and to the left be negative.

Step2: Calculate net force for 1

For the first case, $F_{net1}=(20 + 40-15)\text{ N}=45\text{ N}$. Since the result is positive, the direction is to the right.

Step3: Calculate net force for 2

For the second case, $F_{net2}=(7 - 19)\text{ N}=- 12\text{ N}$. Since the result is negative, the direction is to the left.

Step4: Calculate net force for 3

For the third case, $F_{net3}=(45+3 - 35 - 13)\text{ N}=0\text{ N}$. There is no net - force, so no direction of movement.

Step5: Calculate net force for 4

For the fourth case, $F_{net4}=(11 + 39)\text{ N}=50\text{ N}$. Since the result is positive, the direction is to the right.

Answer:

1. Net Force: $45\text{ N}$, Direction: To the right
2. Net Force: $12\text{ N}$, Direction: To the left
3. Net Force: $0\text{ N}$, Direction: No movement
4. Net Force: $50\text{ N}$, Direction: To the right