1. the density of silver (ag) is 10.5 g/cm³. find the mass of ag that occupies 965 cm³ of space.
2. a 2.75 kg sample of a substance occupies a volume of 250.0 cm³. find its density in g/cm³.
3. under certain conditions, oxygen gas (o₂) has a density of 0.00134 g/ml. find the volume occupied by 250.0 g of o₂ under the same conditions.
4. find the volume that 35.2 g of carbon tetrachloride (ccl₄) will occupy if it has a density of 1.60 g/ml.
5. the density of ethanol is 0.789 g/ml. find the mass of a sample of ethanol that has a volume of 150.0 ml.
6. 30.0 g of each of the following acids are needed. find the volume of each that must be measured out in a graduated cylinder.
a. hydrochloric acid (hcl), density = 1.164 g/ml
b. sulfuric acid (h₂so₄), density = 1.834 g/ml
c. nitric acid (hno₃), density = 1.251 g/ml
7. a rectangular block of lead (pb) measures 20.0 mm x 30.0 mm x 45.0 mm. if the density of pb is 11.34 g/cm³, calculate the mass of the block.
8. a cube of gold (au) has a side length of 1.55 cm. if the sample is found to have a mass of 71.9 g, find the density of au.
9. an irregularly - shaped sample of aluminum (al) is put on a balance and found to have a mass of 43.6 g. the student decides to use the water - displacement method to find the volume. the initial volume reading is 25.5 ml and, after the al sample is added, the water level has risen to 41.7 ml. find the density of the al sample in g/cm³. (remember: 1 ml = 1 cm³.)

Question

Accepted Answer

### 1.
# Explanation:
## Step1: Recall density formula
The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass and $V$ is volume. We want to find $m$, so we can re - arrange it to $m =
ho	imes V$.
Given $
ho = 10.5\ g/cm^{3}$ and $V=965\ cm^{3}$.
$m=
ho	imes V=10.5\ g/cm^{3}	imes965\ cm^{3}$
## Step2: Calculate the mass
$m = 10.5	imes965=10132.5\ g$
# Answer:
$10132.5\ g$

### 2.
# Explanation:
## Step1: Convert mass to grams
First, convert the mass from $kg$ to $g$. Since $1\ kg = 1000\ g$, a $2.75\ kg$ sample has a mass of $m = 2.75	imes1000=2750\ g$.
The volume $V = 250.0\ cm^{3}$.
Use the density formula $
ho=\frac{m}{V}$.
$
ho=\frac{2750\ g}{250.0\ cm^{3}}$
## Step2: Calculate the density
$
ho = 11\ g/cm^{3}$
# Answer:
$11\ g/cm^{3}$

### 3.
# Explanation:
## Step1: Recall density formula and re - arrange
The density formula is $
ho=\frac{m}{V}$, re - arrange it to $V=\frac{m}{
ho}$.
Given $m = 250.0\ g$ and $
ho=0.00134\ g/mL$.
$V=\frac{250.0\ g}{0.00134\ g/mL}$
## Step2: Calculate the volume
$V=\frac{250.0}{0.00134}\approx186567.16\ mL$
# Answer:
$186567.16\ mL$

### 4.
# Explanation:
## Step1: Recall density formula and re - arrange
Using $
ho=\frac{m}{V}$, re - arrange to $V=\frac{m}{
ho}$.
Given $m = 35.2\ g$ and $
ho = 1.60\ g/mL$.
$V=\frac{35.2\ g}{1.60\ g/mL}$
## Step2: Calculate the volume
$V = 22\ mL$
# Answer:
$22\ mL$

### 5.
# Explanation:
## Step1: Use density formula
From $
ho=\frac{m}{V}$, we can find $m$ when $V = 150.0\ mL$ and $
ho=0.789\ g/mL$.
$m=
ho	imes V=0.789\ g/mL	imes150.0\ mL$
## Step2: Calculate the mass
$m=0.789	imes150.0 = 118.35\ g$
# Answer:
$118.35\ g$

### 6A.
# Explanation:
## Step1: Recall density formula and re - arrange
Using $
ho=\frac{m}{V}$, re - arrange to $V=\frac{m}{
ho}$.
Given $m = 30.0\ g$ and $
ho = 1.164\ g/mL$.
$V=\frac{30.0\ g}{1.164\ g/mL}$
## Step2: Calculate the volume
$V=\frac{30.0}{1.164}\approx25.8\ mL$
# Answer:
$25.8\ mL$

### 6B.
# Explanation:
## Step1: Recall density formula and re - arrange
Using $
ho=\frac{m}{V}$, re - arrange to $V=\frac{m}{
ho}$.
Given $m = 30.0\ g$ and $
ho = 1.834\ g/mL$.
$V=\frac{30.0\ g}{1.834\ g/mL}$
## Step2: Calculate the volume
$V=\frac{30.0}{1.834}\approx16.46\ mL$
# Answer:
$16.46\ mL$

### 6C.
# Explanation:
## Step1: Recall density formula and re - arrange
Using $
ho=\frac{m}{V}$, re - arrange to $V=\frac{m}{
ho}$.
Given $m = 30.0\ g$ and $
ho = 1.251\ g/mL$.
$V=\frac{30.0\ g}{1.251\ g/mL}$
## Step2: Calculate the volume
$V=\frac{30.0}{1.251}\approx23.98\ mL$
# Answer:
$23.98\ mL$

### 7.
# Explanation:
## Step1: Calculate the volume of the rectangular block
The volume of a rectangular block $V=l	imes w	imes h$.
$l = 20.0\ mm=2.00\ cm$, $w = 30.0\ mm = 3.00\ cm$, $h = 45.0\ mm=4.50\ cm$.
$V=2.00\ cm	imes3.00\ cm	imes4.50\ cm = 27\ cm^{3}$
Using $
ho=\frac{m}{V}$, we can find $m$. Given $
ho = 11.34\ g/cm^{3}$.
$m=
ho	imes V=11.34\ g/cm^{3}	imes27\ cm^{3}$
## Step2: Calculate the mass
$m=11.34	imes27 = 306.18\ g$
# Answer:
$306.18\ g$

### 8.
# Explanation:
## Step1: Calculate the volume of the cube
The volume of a cube $V = s^{3}$, where $s = 1.55\ cm$.
$V=(1.55\ cm)^{3}=1.55	imes1.55	imes1.55 = 3.723875\ cm^{3}$
Using $
ho=\frac{m}{V}$, given $m = 71.9\ g$.
$
ho=\frac{71.9\ g}{3.723875\ cm^{3}}$
## Step2: Calculate the density
$
ho=\frac{71.9}{3.723875}\approx19.3\ g/cm^{3}$
# Answer:
$19.3\ g/cm^{3}$

### 9.
# Explanation:
## Step1: Calculate the volume of the aluminum sample
The volume of the aluminum sample $V$ is found by the water - displacement method.
$V=41.7\ mL - 25.5\ mL=16.2\ mL = 16.2\ cm^{3}$
Using $
ho=\frac{m}{V}$, given $m = 43.6\ g$.
$
ho=\frac{43.6\ g}{16.2\ cm^{3}}$
## Step2: Calculate the density
$
ho=\frac{43.6}{16.2}\approx2.69\ g/cm^{3}$
# Answer:
$2.69\ g/cm^{3}$

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QUESTION IMAGE

Question

Explanation:

1.

Step1: Recall density formula

Step2: Calculate the mass

Step1: Convert mass to grams

Step2: Calculate the density

Step1: Recall density formula and re - arrange

Step2: Calculate the volume

Answer:

2.