Question

desmond bought a box of bark biscuit bites for his dog, champ. champs favorite flavor is bacon. each dog biscuit has a 25% chance of being bacon - flavored, and desmond takes 3 dog biscuits from the box. how likely is it that all 3 dog biscuits are bacon - flavored? which simulation could be used to fairly represent the situation? flip a pair of coins 3 times. each time the coins both land on heads, it represents a bacon - flavored dog biscuit. roll a six - sided die 3 times. each time 1 appears, it represents a bacon - flavored dog biscuit. use a computer to randomly generate 4 numbers from 1 to 4. each time 3 appears, it represents a bacon - flavored dog biscuit.

Explanation:

Step1: Determine the probability of a single - bacon - flavored biscuit

The probability that a single dog biscuit is bacon - flavored is $p = 0.25=\frac{1}{4}$.

Step2: Analyze each simulation method

• For flipping a pair of coins: The probability of getting two heads when flipping a pair of coins is $\frac{1}{2}\times\frac{1}{2}=\frac{1}{4}$. But we need to do this 3 times to represent 3 biscuits.
• For rolling a six - sided die: The probability of getting a 1 when rolling a six - sided die is $\frac{1}{6}

eq\frac{1}{4}$.

• For generating numbers from 1 to 4: The probability of generating the number 3 (or any single number) from 1 to 4 is $\frac{1}{4}$. But we need to generate 3 numbers to represent 3 biscuits, and generating 4 numbers is not relevant to the 3 - biscuit situation.

The correct simulation is to flip a pair of coins 3 times since the probability of getting two heads (which represents a bacon - flavored biscuit) in a single flip of a pair of coins is the same as the probability of a single dog biscuit being bacon - flavored.

Answer:

Flip a pair of coins 3 times. Each time the coins both land on heads, it represents a bacon - flavored dog biscuit.