Question

determine the concentration in molarity(m) of the following solution: 180 g of trisulfur heptoxide dissolved into 2.40 l of solution. -use correct significant digits and no unit-

Explanation:

Step1: Calculate molar mass of $S_3O_7$

Molar mass of S = 32.07 g/mol, O = 16.00 g/mol
$$\text{Molar mass} = (3 \times 32.07) + (7 \times 16.00) = 96.21 + 112.00 = 208.21\ \text{g/mol}$$

Step2: Find moles of $S_3O_7$

Moles = mass / molar mass
$$\text{Moles} = \frac{180}{208.21} \approx 0.8645$$

Step3: Calculate molarity (M)

Molarity = moles / volume (L)
$$\text{Molarity} = \frac{0.8645}{2.40} \approx 0.36$$

Answer:

0.36