QUESTION IMAGE
Question
determine if each represents a function. if it is not a function, explain why.
- diagram of two - circles with arrows
- {(-2,9),(2,0),(3,6),(4, - 1),(5,9)}
- coordinate - plane with points
- {(-3,2),(2,2),(1,2),(3,1),(0,3)}
- coordinate - plane with a curve
- table with x and y values
evaluate each expression with the given values:
- (n^{2}-3n + 8), if (n = 4)
- (\frac{2-4y}{z}), if (x = 4,y=-3)
- (f(x)=4|x - 2|), find (f(-3))
- find (f(-3)) for (y = f(x)) coordinate - plane with a curve
Step1: Determine if each represents a function
- For 1: In a function, each input (x - value) must have exactly one output (y - value). By vertical - line test (for graphs) or checking the mapping (for sets of ordered pairs), we analyze each case.
- For 2: The set of ordered pairs \(\{( - 2,9),(2,0),(3,6),(4, - 1),(5,9)\}\) is a function since each x - value has a unique y - value.
- For 3: The graph passes the vertical - line test, so it is a function.
- For 4: The set \(\{( - 3,2),( - 2,2),( - 1,2),(0,1),(0,3)\}\) is not a function because \(x = 0\) has two different y - values (\(y=1\) and \(y = 3\)).
- For 5: The graph fails the vertical - line test, so it is not a function.
- For 6: The table represents a function as each x - value has a single y - value.
Step2: Evaluate expressions
For 7:
Substitute \(n = 4\) into \(n^{2}-3n + 8\).
\[
$$\begin{align*}
n^{2}-3n + 8&=(4)^{2}-3\times4 + 8\\
&=16-12 + 8\\
&=4 + 8\\
&=12
\end{align*}$$
\]
For 8:
Substitute \(x = 4\) and \(y=-3\) into \(\frac{2-4y}{2}\).
\[
$$\begin{align*}
\frac{2-4y}{2}&=\frac{2-4\times(-3)}{2}\\
&=\frac{2 + 12}{2}\\
&=\frac{14}{2}\\
&=7
\end{align*}$$
\]
For 9:
Given \(f(x)=4|x - 2|\), substitute \(x=-3\).
\[
$$\begin{align*}
f(-3)&=4|-3 - 2|\\
&=4|-5|\\
&=4\times5\\
&=20
\end{align*}$$
\]
For 10:
From the graph of \(y = f(x)\), when \(x=-3\), find the corresponding y - value. By looking at the graph, \(f(-3)=-7\).
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