Question

determine the name of each compound. use roman numerals where needed. spelling counts. cuo: cu₂o: cos: co₂s₃: febr₂:

Explanation:

Step1: Identify copper oxidation state in CuO

Oxygen has an oxidation - state of - 2. In CuO, for the compound to be neutral, copper has an oxidation state of + 2. So it is copper(II) oxide.

Step2: Identify copper oxidation state in Cu₂O

In Cu₂O, oxygen has an oxidation state of - 2. Let the oxidation state of copper be \(x\). Using the formula \(2x+( - 2)=0\), we get \(x = + 1\). So it is copper(I) oxide.

Step3: Identify cobalt oxidation state in CoS

Sulfur has an oxidation state of - 2. For CoS to be neutral, cobalt has an oxidation state of + 2. So it is cobalt(II) sulfide.

Step4: Identify cobalt oxidation state in Co₂S₃

Sulfur has an oxidation state of - 2. Let the oxidation state of cobalt be \(x\). Using the formula \(2x+3\times(-2)=0\), we solve for \(x\): \(2x - 6 = 0\), so \(x = + 3\). So it is cobalt(III) sulfide.

Step5: Identify iron oxidation state in FeBr₂

Bromine has an oxidation state of - 1. For FeBr₂ to be neutral, iron has an oxidation state of + 2. So it is iron(II) bromide.

Answer:

CuO: copper(II) oxide
Cu₂O: copper(I) oxide
CoS: cobalt(II) sulfide
Co₂S₃: cobalt(III) sulfide
FeBr₂: iron(II) bromide