QUESTION IMAGE
Question
determine which postulate or theorem can be used to prove that △abc = △dcb.
- a. sas
b. aas
c. asa
d. sss
Step1: Identify common side
$BC$ is common to both $\triangle ABC$ and $\triangle DCB$.
Step2: Analyze given markings
We have one - pair of equal sides (marked) and one - pair of equal angles (marked). The equal sides and the equal angles are adjacent to the common side.
Step3: Recall congruence postulates
The Side - Angle - Side (SAS) postulate states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent. Here, we have two sides and the included angle congruent for $\triangle ABC$ and $\triangle DCB$.
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A. SAS