Question

the diagram below shows a ray of light moving from left to right, through the interface between two mediums. snells law is used to determine the direction of the refracted ray. if the index of refraction in the first medium is 1.5 and the index of refraction in the second medium is 1.0, what is the angle of refraction when the angle of incidence is 28°? snells law: $n_1sin(\theta_1)=n_2sin(\theta_2)$ a. 42° b. 45° c. 18°

Explanation:

Step1: Identify values from the problem

$n_1 = 1.5$, $\theta_1=28^{\circ}$, $n_2 = 1.0$

Step2: Apply Snell's Law

$n_1\sin(\theta_1)=n_2\sin(\theta_2)$ becomes $1.5\times\sin(28^{\circ})=1.0\times\sin(\theta_2)$

Step3: Solve for $\sin(\theta_2)$

$\sin(\theta_2)=\frac{1.5\times\sin(28^{\circ})}{1.0}$
$\sin(\theta_2)=1.5\times\sin(28^{\circ})\approx1.5\times0.4695 = 0.70425$

Step4: Find $\theta_2$

$\theta_2=\sin^{- 1}(0.70425)\approx44.7^{\circ}\approx45^{\circ}$

Answer:

B. $45^{\circ}$