Question

the diagrams below show three pure samples of gas in identical closed, rigid containers. each sample contains the same number of gas particles. the particles in gas b and gas c are moving at the same average speed, while the particles in gas a are moving at a higher average speed. each particle in gas a and gas c has the same mass, while each particle in gas b has less mass. order the samples by their gas pressures. higher gas pressure gas c gas a gas b

Explanation:

Step1: Recall pressure - kinetic energy relation

Pressure of a gas is related to the kinetic energy of its particles. Kinetic energy formula is $K = \frac{1}{2}mv^{2}$, where $m$ is mass and $v$ is velocity.

Step2: Analyze gas A

Gas A particles have higher average speed than B and C. Particles of A and C have same mass. Since $K=\frac{1}{2}mv^{2}$, gas A particles have higher kinetic energy than C (due to higher speed) and higher kinetic energy than B (due to both higher speed and higher mass). Higher kinetic - energy means more forceful collisions with the container walls, so higher pressure.

Step3: Analyze gas C and B

Particles of B and C have same speed, but C particles have more mass. Using $K=\frac{1}{2}mv^{2}$, C particles have higher kinetic energy than B particles. So C has higher pressure than B.

Answer:

gas A, gas C, gas B