Question

divide. if the polynomial does not divide evenly, include the remainder as a fraction.\\((6b^{2}-61b + 12)div(b - 10)\\)

Explanation:

Step1: Divide leading terms

$\frac{6b^2}{b} = 6b$

Step2: Multiply divisor by result

$6b \times (b - 10) = 6b^2 - 60b$

Step3: Subtract from dividend

$(6b^2 - 61b + 12) - (6b^2 - 60b) = -b + 12$

Step4: Divide new leading term

$\frac{-b}{b} = -1$

Step5: Multiply divisor by result

$-1 \times (b - 10) = -b + 10$

Step6: Subtract to get remainder

$(-b + 12) - (-b + 10) = 2$

Answer:

$6b - 1 + \frac{2}{b - 10}$