Question

1. drag and drop the electron configurations to the elements. refer to the periodic table.

choices
n
zn
al
cl
1s²2s²2p³
1s²2s²2p⁶3s²3p⁵
1s²2s²2p⁶3s²3p¹
1s²2s²2p⁶3s²3p⁶4s²3d¹⁰

Explanation:

1. Calculate total electrons from each configuration, match to element atomic number:

• For $1s^22s^22p^63s^23p^5$: Sum electrons = 2+2+6+2+5=17, which matches Chlorine (Cl, atomic number 17).
• For $1s^22s^22p^3$: Sum electrons = 2+2+3=7, which matches Nitrogen (N, atomic number 7).
• For $1s^22s^22p^63s^23p^1$: Sum electrons = 2+2+6+2+1=13, which matches Aluminum (Al, atomic number 13).
• For $1s^22s^22p^63s^23p^64s^23d^{10}$: Sum electrons = 2+2+6+2+6+2+10=30, which matches Zinc (Zn, atomic number 30).

Answer:

• $1s^22s^22p^63s^23p^5$ → Cl
• $1s^22s^22p^3$ → N
• $1s^22s^22p^63s^23p^1$ → Al
• $1s^22s^22p^63s^23p^64s^23d^{10}$ → Zn