Question

drag each value to the correct location on the equation. not all values will be used.
a company sells lab equipment. the daily revenue and costs are modeled by the functions below where x is the number of units sold.
revenue : ( r(x) = -0.32x^2 + 270x )
costs : ( c(x) = 70x + 52 )
determine the function representing the total daily profit, ( p(x) ), after selling x units.
( p(x) = square x^2 + square x + square )
(values: 52, -0.32, 340, 200, 0.32)
reset next

Explanation:

Step1: Recall Profit Formula

Profit \( P(x) \) is revenue minus costs, so \( P(x)=R(x)-C(x) \).

Step2: Substitute \( R(x) \) and \( C(x) \)

Given \( R(x) = -0.32x^2 + 270x \) and \( C(x)=70x + 52 \), substitute into the profit formula:
\( P(x)=(-0.32x^2 + 270x)-(70x + 52) \)

Step3: Simplify the Expression

Distribute the negative sign: \( P(x)= -0.32x^2 + 270x - 70x - 52 \)
Combine like terms (\( 270x - 70x = 200x \)): \( P(x)= -0.32x^2 + 200x - 52 \)

Answer:

\( P(x) = -0.32x^2 + 200x - 52 \) (So the coefficients for \( x^2 \) is -0.32, for \( x \) is 200, and the constant term is -52)