Question

drag the tiles to the correct boxes to complete the pairs.
the table gives the masses of the three fundamental particles of an atom. match each combination of particles with its total mass. round the first factors to four decimal places.
particle mass (grams)
proton $1.6726 \times 10^{-24}$
neutron $1.6749 \times 10^{-24}$
electron $9.108 \times 10^{-28}$
two protons and one neutron
two electrons and one proton
one electron, one proton, and one neutron
one proton and two neutrons
mass
particles
$1.6744 \times 10^{-24}$ grams
$5.0201 \times 10^{-24}$ grams
$5.0224 \times 10^{-24}$ grams
$3.3484 \times 10^{-24}$ grams

Explanation:

Step1: Calculate mass of 2 electrons +1 proton

First, convert electron mass to $10^{-24}$: $9.108 \times 10^{-28} = 0.0009108 \times 10^{-24}$.
Total mass: $2\times0.0009108 \times 10^{-24} + 1.6726 \times 10^{-24} = (0.0018216 + 1.6726) \times 10^{-24} = 1.6744216 \times 10^{-24} \approx 1.6744 \times 10^{-24}$ grams

Step2: Calculate mass of 1 proton +2 neutrons

Total mass: $1.6726 \times 10^{-24} + 2\times1.6749 \times 10^{-24} = (1.6726 + 3.3498) \times 10^{-24} = 5.0224 \times 10^{-24}$ grams

Step3: Calculate mass of 2 protons +1 neutron

Total mass: $2\times1.6726 \times 10^{-24} + 1.6749 \times 10^{-24} = (3.3452 + 1.6749) \times 10^{-24} = 5.0201 \times 10^{-24}$ grams

Step4: Calculate mass of 1e,1p,1n

Total mass: $0.0009108 \times 10^{-24} + 1.6726 \times 10^{-24} + 1.6749 \times 10^{-24} = (0.0009108 + 1.6726 + 1.6749) \times 10^{-24} = 3.3484108 \times 10^{-24} \approx 3.3484 \times 10^{-24}$ grams

Answer:

$1.6744 \times 10^{-24}$ grams $
ightarrow$ two electrons and one proton
$5.0201 \times 10^{-24}$ grams $
ightarrow$ two protons and one neutron
$5.0224 \times 10^{-24}$ grams $
ightarrow$ one proton and two neutrons
$3.3484 \times 10^{-24}$ grams $
ightarrow$ one electron, one proton, and one neutron