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draw the lewis structure created by the curved arrow. write in formal c…

Question

draw the lewis structure created by the curved arrow. write in formal charges wherever they are not equal to zero.

Explanation:

Step1: Follow the curved - arrow movement

The curved arrow indicates that the lone - pair on the negatively charged nitrogen is being donated to the positively charged carbon.

Step2: Redraw the Lewis structure

The new structure will have a double - bond between the carbon and the nitrogen that was previously negatively charged. The formal charges will be recalculated. The formula for formal charge is $FC = V - N_b - \frac{B}{2}$, where $V$ is the number of valence electrons, $N_b$ is the number of non - bonding electrons, and $B$ is the number of bonding electrons.
For the original positively charged carbon: $V = 4$, $N_b=0$, $B = 8$, so $FC=4 - 0-\frac{8}{2}=0$.
For the original negatively charged nitrogen: $V = 5$, $N_b = 2$, $B = 6$, so $FC = 5 - 2-\frac{6}{2}=0$.

Step3: Draw the new Lewis structure

The new Lewis structure has a double - bond between carbon and nitrogen. Carbon is bonded to two hydrogens and a nitrogen with a single bond, and the other nitrogen is bonded to two hydrogens and has a double - bond with carbon. There are no non - zero formal charges.

Answer:

H
|
H - C = N - H
|
H