Question

drop the correct answer into each box to match each equation with its solution
$x^3=-125$
$2x^3=128$
$-3x^3+10=34$
$x^3-2=-1$
$25-6x^3=31$
$x=-5$
$x=-4$
$x=-2$
$x=-1$
$x=1$

Explanation:

Step1: Solve $x^3=-125$

Take cube root of both sides:
$x = \sqrt[3]{-125} = -5$

Step2: Solve $2x^3=128$

Divide both sides by 2:
$x^3 = \frac{128}{2} = 64$
Take cube root:
$x = \sqrt[3]{64} = 4$

Step3: Solve $-3x^3+10=34$

Subtract 10 from both sides:
$-3x^3 = 34 - 10 = 24$
Divide by -3:
$x^3 = \frac{24}{-3} = -8$
Take cube root:
$x = \sqrt[3]{-8} = -2$

Step4: Solve $x^3-2=-1$

Add 2 to both sides:
$x^3 = -1 + 2 = 1$
Take cube root:
$x = \sqrt[3]{1} = 1$

Step5: Solve $25-6x^3=31$

Subtract 25 from both sides:
$-6x^3 = 31 - 25 = 6$
Divide by -6:
$x^3 = \frac{6}{-6} = -1$
Take cube root:
$x = \sqrt[3]{-1} = -1$

Answer:

$x^3=-125$ matches $x=-5$
$2x^3=128$ matches $x=4$
$-3x^3+10=34$ matches $x=-2$
$x^3-2=-1$ matches $x=1$
$25-6x^3=31$ matches $x=-1$