Question

duce the radical.
\sqrt{112}
\sqrt{\square} \sqrt{\square}

Explanation:

Step1: Factor out perfect square

$\sqrt{112} = \sqrt{16 \times 7}$

Step2: Split radical into product

$\sqrt{16 \times 7} = \sqrt{16} \sqrt{7}$

Answer:

$\sqrt{16} \sqrt{7}$ (or simplified fully as $4\sqrt{7}$)