Question

2 during a memorial airshow (like the ones flown at major state events) an airplane of mass 5000 kg is 300 m above the ground and moving at 60 m/s. how much total energy does the airplane have?

Explanation:

Step1: Calculate potential energy

The formula for gravitational - potential energy is $U = mgh$, where $m = 5000\ kg$, $g= 9.8\ m/s^{2}$, and $h = 300\ m$.
$U=5000\times9.8\times300 = 14700000\ J$.

Step2: Calculate kinetic energy

The formula for kinetic energy is $K=\frac{1}{2}mv^{2}$, where $m = 5000\ kg$ and $v = 60\ m/s$.
$K=\frac{1}{2}\times5000\times60^{2}=9000000\ J$.

Step3: Calculate total energy

The total mechanical energy $E$ is the sum of potential energy $U$ and kinetic energy $K$.
$E=U + K=14700000+9000000=23700000\ J$.

Answer:

$23700000\ J$