Question

1. during primrose schools annual walk for education, reba walked $5\frac{5}{6}$ laps around the track. holt walked $1\frac{3}{5}$ more laps than reba did. how many laps did holt walk?

a $6\frac{13}{30}$
b $7\frac{13}{30}$
c $7\frac{13}{15}$
d $7\frac{1}{2}$

Explanation:

Step1: Convert mixed numbers to improper fractions

Reba's laps: \( 5\frac{5}{6}=\frac{5\times6 + 5}{6}=\frac{35}{6} \)
Holt's extra laps: \( 1\frac{3}{5}=\frac{1\times5+3}{5}=\frac{8}{5} \)

Step2: Find a common denominator and add

Common denominator of 6 and 5 is 30.
\( \frac{35}{6}=\frac{35\times5}{6\times5}=\frac{175}{30} \)
\( \frac{8}{5}=\frac{8\times6}{5\times6}=\frac{48}{30} \)
Sum: \( \frac{175}{30}+\frac{48}{30}=\frac{223}{30} \)

Step3: Convert back to mixed number

\( \frac{223}{30}=7\frac{13}{30} \) (since \( 30\times7 = 210 \), \( 223 - 210 = 13 \))

Answer:

B. \( 7\frac{13}{30} \)