Question

for each list, circle the one that is not equivalent to the rest. 9.) -\frac{a}{b},\frac{-a}{-b},\frac{-a}{b},\frac{a}{-b},-1\frac{a}{b} 10.) \frac{x}{y},-\frac{x}{y},\frac{-x}{-y},-(\frac{-x}{y}) 11.) -(\frac{-3}{-7}),\frac{-3}{7},-(\frac{3}{7}),-(\frac{3}{-7}) 12.) -\frac{-1}{x},\frac{-1}{-x},\frac{1}{x},-\frac{1}{x} which of the following have a value of -2? circle all that apply.

Explanation:

Step1: Simplify each fraction in 9.

$-\frac{a}{b}$ is as - is. $\frac{-a}{-b}=\frac{a}{b}$, $\frac{-a}{b}=-\frac{a}{b}$, $\frac{a}{-b}=-\frac{a}{b}$, $- 1\frac{a}{b}=-\frac{a}{b}$. So $\frac{-a}{-b}$ is not equivalent to the rest.

Step2: Simplify each fraction in 10.

$\frac{x}{y}$ is as - is. $-\frac{x}{y}$ is negative. $\frac{-x}{-y}=\frac{x}{y}$, $-(\frac{-x}{y})=\frac{x}{y}$. So $-\frac{x}{y}$ is not equivalent to the rest.

Step3: Simplify each fraction in 11.

$-(\frac{-3}{-7})=-\frac{3}{7}$, $\frac{-3}{7}=-\frac{3}{7}$, $-(\frac{3}{7})=-\frac{3}{7}$, $-(\frac{3}{-7})=\frac{3}{7}$. So $-(\frac{3}{-7})$ is not equivalent to the rest.

Step4: Simplify each fraction in 12.

$-\frac{-1}{x}=\frac{1}{x}$, $\frac{-1}{-x}=\frac{1}{x}$, $\frac{1}{x}$ is as - is, $-\frac{1}{x}$ is negative. So $-\frac{1}{x}$ is not equivalent to the rest.

Answer:

1. $\frac{-a}{-b}$
2. $-\frac{x}{y}$
3. $-(\frac{3}{-7})$
4. $-\frac{1}{x}$