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for each row in the table below, decide whether the pair of elements wi…

Question

for each row in the table below, decide whether the pair of elements will form a molecular or ionic compound. if they will, then enter the chemical formula of the compound. if the elements will form more than one compound, enter the compound with the fewest total number of atoms. you may assume all chemical bonds are single bonds, not double or triple bonds. table with columns: element #1, element #2, compound formed? (options: ionic, molecular, neither), chemical formula. rows: 1. element #1: carbon, element #2: chlorine; 2. element #1: sodium, element #2: lithium; 3. element #1: sulfur, element #2: chlorine

Explanation:

Response
Row 1: Carbon (C) and Chlorine (Cl)

Step1: Determine Bond Type and Compound Type

Carbon is a non - metal and Chlorine is a non - metal. Non - metal + non - metal forms a molecular compound. Carbon has a valency of 4 (needs 4 electrons to complete octet) and Chlorine has a valency of 1 (needs 1 electron to complete octet). So carbon will bond with 4 chlorine atoms.

Step2: Write the Chemical Formula

The chemical formula is $CCl_4$. The compound is molecular.

Row 2: Sodium (Na) and Lithium (Li)

Step1: Determine Bond Type and Compound Type

Sodium and Lithium are both metals. Metals do not form compounds with each other (they don't transfer or share electrons in a way to form a stable compound in the typical sense here). So the compound type is neither. And there is no chemical formula as they don't form a compound.

Row 3: Sulfur (S) and Chlorine (Cl)

Step1: Determine Bond Type and Compound Type

Sulfur is a non - metal and Chlorine is a non - metal. So they form a molecular compound. Sulfur has a valency of 2 (can share 2 electrons) and Chlorine has a valency of 1. So sulfur will bond with 2 chlorine atoms.

Step2: Write the Chemical Formula

The chemical formula is $SCl_2$. The compound is molecular.

Answer:

element #1element #2compound formed?chemical formula
sodiumlithiumneither-
sulfurchlorinemolecular$SCl_2$