Question

eams
counting atoms
date
name
count how many atoms for each compound or molecule and then draw each molecule/compound
$ce{nahco_{3}}$
$ce{c_{2}h_{4}o_{2}}$

Explanation:

Step1: Count atoms in $\text{NaHCO}_3$

Sodium ($\text{Na}$): 1, Hydrogen ($\text{H}$): 1, Carbon ($\text{C}$): 1, Oxygen ($\text{O}$): 3

Step2: Count atoms in $\text{C}_2\text{H}_4\text{O}_2$

Carbon ($\text{C}$): 2, Hydrogen ($\text{H}$): 4, Oxygen ($\text{O}$): 2

Step3: Summarize total atoms per compound

For $\text{NaHCO}_3$: $1+1+1+3=6$ total atoms; for $\text{C}_2\text{H}_4\text{O}_2$: $2+4+2=8$ total atoms

Answer:

1. For $\boldsymbol{\text{NaHCO}_3}$:

• Sodium ($\text{Na}$): 1 atom
• Hydrogen ($\text{H}$): 1 atom
• Carbon ($\text{C}$): 1 atom
• Oxygen ($\text{O}$): 3 atoms
• Total atoms: 6

1. For $\boldsymbol{\text{C}_2\text{H}_4\text{O}_2}$:

• Carbon ($\text{C}$): 2 atoms
• Hydrogen ($\text{H}$): 4 atoms
• Oxygen ($\text{O}$): 2 atoms
• Total atoms: 8

*(Note: Molecular structure drawings:

• $\text{NaHCO}_3$: Ionic structure with $\text{Na}^+$ cation and $\text{HCO}_3^-$ anion (the anion has a central C bonded to one O, one OH, and one double-bonded O)
• $\text{C}_2\text{H}_4\text{O}_2$ (acetic acid): $\text{CH}_3-\text{COOH}$, with a $\text{CH}_3$ group bonded to a carbonyl ($\text{C=O}$) and a hydroxyl ($\text{-OH}$) group)*