Question

an ebony carving has a mass of 273 g and a volume of 207 cm³. express your answer with the appropriate units. part b a 14.3 cm³ sample of tin has a mass of 0.104 kg. express your answer with the appropriate units. part c a bottle of acetone (fingernail polish remover) contains 55.0 ml of acetone. if the acetone has a mass of 43.5 g, what is the density of acetone? express your answer with the appropriate units.

Explanation:

Step1: Recall density formula

The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass and $V$ is volume.

Step2: Solve Part A

Given $m = 273\ g$ and $V=207\ cm^{3}$, then $
ho_A=\frac{273\ g}{207\ cm^{3}}\approx1.32\ g/cm^{3}$.

Step3: Solve Part B

First convert mass to grams: $m = 0.104\ kg=104\ g$, $V = 14.3\ cm^{3}$. Then $
ho_B=\frac{104\ g}{14.3\ cm^{3}}\approx7.27\ g/cm^{3}$.

Step4: Solve Part C

Given $m = 43.5\ g$ and $V = 55.0\ mL$ (since $1\ mL = 1\ cm^{3}$), then $
ho_C=\frac{43.5\ g}{55.0\ cm^{3}}\approx0.791\ g/cm^{3}$.

Answer:

Part A: Value: $1.32$, Units: $g/cm^{3}$
Part B: Value: $7.27$, Units: $g/cm^{3}$
Part C: Value: $0.791$, Units: $g/cm^{3}$