Question

edwards class collected signatures for a petition. by the end, 6 students had collected: 84 signatures 71 signatures 98 signatures 50 signatures 96 signatures 99 signatures what was the mean absolute deviation of the numbers of signatures collected? if the answer is a decimal, round it to the nearest tenth. mean absolute deviation (mad): signatures

Explanation:

Step1: Calculate the mean

The data set is \(84, 71, 98, 50, 96, 99\). The mean \(\bar{x}=\frac{84 + 71+98+50+96+99}{6}=\frac{498}{6}=83\).

Step2: Calculate the absolute - deviations

\(\vert84 - 83\vert=1\), \(\vert71 - 83\vert = 12\), \(\vert98 - 83\vert=15\), \(\vert50 - 83\vert = 33\), \(\vert96 - 83\vert=13\), \(\vert99 - 83\vert=16\).

Step3: Calculate the mean of the absolute - deviations

The mean absolute deviation \(MAD=\frac{1+12 + 15+33+13+16}{6}=\frac{90}{6}=15.0\).

Answer:

15.0